Question

A town has a population of 18000 and grows at 2% every year. What will be the population after 11 years, to the nearest whole number?

Answer 1

~22381

Explanation:

a=starting value = 18000

r=rate = 2%=0.02

Exponential Growth:

b=1+r=1+0.02=1.02

b=1+r=1+0.02=1.02

Write Exponential Function:

y=18000(1.02)^x

y=18000(1.02)

x

Put it all together

\text{Plug in time for x:}

Plug in time for x:

y=18000(1.02)^{11}

y=18000(1.02)

11

Evauate:

y= 22380.73755

y=22380.73755

Round:

y\approx 22381

y≈22381