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1 vote
Subtract:
(6)/(2x^2+8x) -(x)/(4x^2+12-16) =(6)/(2x(x+4)) -(x)/(4(x+4)(x-1)) =(6*2(x-1))/(2x(x+4)*2(x-1)) -(x*x)/(4(x+4)(x-1)*x)

A:
(-2x^2+12x-12)/(2(x+4)(x-1))
B:
(-x^2+6x-6)/(2(x+4)(x-1))
C:
(-2x^2+12x-12)/(4(x+4)(x-1))
D:
(-x^2+12x-12)/(4x(x+4)(x-1))

User Csaxena
by
3.1k points

1 Answer

5 votes

Explanation:

I think D

User Nikeros
by
3.1k points