Answer:
1) (5 moles of calcium bromide) x 2 / 1 = 10 moles
2) (2.00 moles of calcium bromide) = 2.00 moles of calcium sulfate
so (2.00) x (136.1 g/mol) = 272.2 g
3) (845 grams of calcium sulfate) / 136.14 g/mol = 6.21 moles
6.21 moles of calcium sulfate = 6.21 moles of calcium bromide
(6.21 moles of calcium bromide) x 199.89 g/mol = 1241.32 g