Question

14. A square has a perimeter of 36 units. One vertex of the square is located at (3,5) on the coordinate grid, What could be the x- and y-coordinates of another vertex of the square?​

Answer 1

For a square of side length L, the perimeter is:

P = 4*L

Then if the perimeter of our square is 36 units, we have:

36 units = 4*L

(36 units)/4 = L = 9 units.

Now we know that one vertex of the square is located at (3, 5)

Then another vertex of the square can be at:

A distance of 9 units of this point (such that these vertices are connected by one side of the square)

Some examples can be:

(3 + 9, 5) = (12, 5)

or

(3, 5 + 9) = (3, 14)

These are the simpler options, there are a lot of other possible points that can be another vertes (we can have a circle of radius 9 units centered in the point (3, 5), all these points can be another vertex of the square).

We also can have a vertex that is connected by the diagonal, this point can be:

(3 + 9, 5 + 9) = (12, 14)

or

(3 - 9, 5 - 9) = (-6, -4)

Again, there are a lot of other possible points that can be this vertex (A circle of radius √2*9 units centered in the point (3, 5)).