Question

Points A, R and G are points of tangency. Find the perimeter of ∆NET below.

Answer 1

`\small\mathfrak\red{here \: is \: your \: solution..} \\ \\ we \: know \: that \: tangent \\ from \: a \: same point \: are \: equal \\ \\ tr = 9 | an = 7 | eg = 5 \\ \\ tr = ta | an = gn | eg = re \\ \\ ta = 9 | gn =7 | re = 5 \\ \\ hence \: perimeter \: = 2(9 + 7 + 5) \\ \\ perimeter = 42 \: \\ \\ \huge\mathfrak\purple{hope \: it \: helps...}`