Question

Find all the zeros of the function: f(x) = x^2 - 2x - 3

Answer 1

x= 3 and -1

Explanation:

`f(x) = {x}^(2) - 2x - 3`

add three to both sides

`3 = {x}^(2) - 2x`

figure out what half of -2 is

half of -2 is (-1) than square that (-1)^2=1

the 1 is what you add to both sides

`3 + 1 = {x}^(2) - 2x + 1 \\ 4 = {(x - 1)}^(2)`

than take the square root of both sides

`√(4) = \sqrt{ {(x - 1)}^(2) }`

this than equals

+2=x-1

than to find the x values

2=x-1

+1 +1

3=x

-2=x-1

+1 +1

-1=x