Question

A taxi accelerates from 10m/s to 28m/s in 6sec find the average acceleration ?​

Answer 1

3m/s^-2

Step-by-step explanation:

a=(v-u)/t where v is the final velocity at 28 m/s and u is the initial velocity at 10m/s and t is the time taken at 6 seconds

a=(28-10)/6 = 3