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What is the percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution?

User Byte Brad
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Answer: The percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.

Step-by-step explanation:

Given: Volume of solute = 120 mL

Volume of solvent = 350 mL

Now, total volume of the solution is as follows.


V_(total) = V_(solute) + V_(solvent)\\= 120 mL + 350 mL\\= 470 mL

Let us assume that 100 mL of solution is taken and the amount of isopropyl alcohol present in it is as follows.


(V_(solute))/(V_(total)) * 100 mL\\(120 mL)/(470) * 100 mL\\= 25.53 mL

Hence, there is 25.53 mL isopropyl alcohol is present in 100 mL of solution. Therefore, %v/v is calculated as follows.


Percent (v/v) = (25.53 mL)/(100 mL)\\= 25.5%

Thus, we can conclude that the percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.

User Hss
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