Question

What is the y value where the hole is located in this equation. Show your work. f(x)= (4x-4) x (x-12)/(x-12)

Answer 1

y = 44

Explanation:

Given

f(x) =
`((4x-4)(x-12))/(x-12)` ← cancel the factor (x - 12)

= 4x-4

Removing this factor creates a hole at

x - 12 = 0 ⇒ x = 12

Substitute x = 12 into the simplified f(x)

y = 4(12) - 4 = 48 - 4 = 44

That is hole at (12, 44 )