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Find the zeros of the quadratic function: y=x^2-4x-12
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Find the zeros of the quadratic function: y=x^2-4x-12

User Stuckj
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Answer:


x {}^(2) - 4x - 12 = 0 \\ (x - 6)(x + 2) = 0 \\ x = 6 \: \: x = - 2

User Verthosa
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