Question

A 752g sample of an unknown substance has its temperature increase by 8°C after being exposed to 1287.424 j,calculate the specific heat of

the substance. _____J/g*C (3 sig figs)

Answer 1

0.214 J/g.°C

Step-by-step explanation:

Step 1: Given data

• Mass of the sample (m): 752 g

• Temperature increase (ΔT): 8 °C

• Provided heat (Q): 1287.424 J

Step 2: Calculate the specific heat of the substance (c)

The specific heat of the substance is an intrinsic property of a substance. We can calculate it using the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 1287.424 J / 752 g × 8 °C = 0.214 J/g.°C