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Ln cos2y + xy + 5x² = 5, find dy/dx. HELP PLEASE!!! ​
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Ln cos2y + xy + 5x² = 5, find dy/dx. HELP PLEASE!!!

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Ln cos2y + xy + 5x² = 5, find dy/dx. HELP PLEASE!!! ​-example-1
User Nouseforname
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1 Answer

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In order of steps
(1/cos2y)(-sin2y)(2dy/dx) +dy/dx + 10x= 0
Pull out dy/dx
Dy/dx[(-2sin2y/cos2y)+1] =-10x
Get dy/dx by itself
Dy/dx=-10x/[-2tan2y+1]

I THINK
I just finished calc 2 but i think by process is correct
User Alex Stybaev
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