Answer:
–6562.816 J
Step-by-step explanation:
From the question given above, the following data were obtained:
Msss (M) = 256 g
Initial temperature (T₁) = 96 °C
Final temperature (T₂) = 28 °C
Heat (Q) released =?
Next, we shall determine the change in temperature. This can be obtained as follow:
Initial temperature (T₁) = 96 °C
Final temperature (T₂) = 28 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 28 – 96
ΔT = –68 °C
Finally, we shall determine the heat released. This can be obtained as follow:
Msss (M) = 256 g
Change in temperature (ΔT) = –68 °C
Specific heat capacity (C) of Zn = 0.377 J/gºC
Heat (Q) released =?
Q = MCΔT
Q = 256 × 0.377 × –68
Q = –6562.816 J
Thus, –6562.816 J of heat energy is released.