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The 10th term of the arithmetic 5x + 6, 11x + 2, 17x - 2,

User Telebog
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1 Answer

3 votes

Answer:

t10 = 59x - 30

Explanation:

a = 5x + 6

d = 11x + 2 - 5x - 6

d = 6x - 4

n = 10

tn = a + (n - 1)*d

t10 = 5x + 6 + (10 - 1) ( 6x - 4)

t10 = 5x + 6 + 9(6x - 4)

t10 = 5x + 6 + 54x - 36

t10 = 59x - 30

Check by finding the 3rd term

d = 6x - 4

n = 3

a = 5x + 6

t3 = 5x + 6 + (3-1)*(6x - 4)

t3 = 5x + 6 + 2(6x - 4)

t3 = 5x + 6 + 12x - 8

t3 = 17x - 2 which is exactly what it should be.

User Maximouse
by
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