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Find two consecutive odd integers such that the sum between twice the smallest and the biggest is 35.

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Answer:

Consecutive odd numbers will be 11 and 13.

Explanation:

Let the two consecutive odd integers are n and (n + 2).

From the given question,

Sum between twice the smallest and the biggest is 35.

Since, smallest number is 'n' and biggest is (n + 2)

Therefore equation will be,

2n + (n + 2) = 35

(2n + n) + 2 = 35

3n + 2 = 35

3n = 33

n = 11

And (n + 2) = 13

Consecutive odd numbers will be,

11, 13

User Yazh
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