Question

How many solutions does the equation 4y + 7 = 5 + 2 + 4y have?

A. One
B. Two
C. None
D. Infinitely many

Answer 1

D :)

Explanation:

Add 55 and 22.

4y+7=7+4y4y+7=7+4y

Move all terms containing yy to the left side of the equation.

Subtract 4y4y from both sides of the equation.

4y+7−4y=74y+7-4y=7

Combine the opposite terms in

Subtract 4y4y from 4y4y.

0+7=70+7=7

Add 00 and 77.

7=77=7

Since 7=77=7, the equation will always be true for any value of yy.

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

(−∞,∞)

Answer 2

D. infinitely many

Explanation:

5+2 = 7 so 4y + 7 = 5 + 2 + 4y just equals 4y + 7=4y + 7 and any value of y is true in that equation.