Question

In triangle ABC, what is the measure of b if a = 51, c = 38, and B = 41°?

Round the answer to the nearest hundredth.

Answer 1

33.46

Explanation:

Using the cosine rule;

b² = a²+c²-2accosB

b² = 51²+38²-2(51)(38)cos41

b² = 2601+1444-2(51)(38)cos41

b² = 4045-2,925.25

b² = 1,119.74

b = √1,119.74

b = 33.46

Hence the value of b to nearest hundredth is 33.46