Question

A sample of methane collected when the temp was 30 C mmHg measures 398 mL. What would be the volume of the sample at -5 C and 616 mmHg pressure

Answer 1

Question

A sample of methane collected when the temp was 30 C and 760mmHg measures 398 mL. What would be the volume of the sample at -5 C and 616 mmHg pressure

Answer:

434.32mL

Step-by-step explanation:

Using the combined gas law:

`(PV)/(T)` = k

Where;

P = Pressure

V = Volume

T = Temperature

k = constant.

It can be deduced that:

`(P_1V_1)/(T_1)` =
`(P_2V_2)/(T_2)` = k ---------------------(i)

Where:

P₁ and P₂ are the initial and final pressures of the given gas

V₁ and V₂ are the initial and final volumes of the given gas

T₁ and T₂ are the initial and final temperatures of the gas.

From the question:

the gas is methane

P₁ = 760mmHg

P₂ = 616mmHg

V₁ = 398mL

V₂ = ?

T₁ = 30°C = (30 +273)K = 303K

T₂ = -5°C = (-5 +273)K = 268K

Substitute these values into equation (i) as follows;

`(760*398)/(303)` =
`(616*V_2)/(268)`

Solve for V₂

V₂ =
`(760*398*268)/(616*303)`

V₂ = 434.32mL

Therefore, the volume of the sample at -5C and 616mmHg pressure is 434.32mL