Question

Find four consecutive even integers such that if the sum of the first and third was multiplied by 2, the result is 20 less than three times the fourth.

Answer 1

xAnswer:

-10 -8 -6 -4

Explanation:

The numbers are

first =x

second= x+2

third=x+4

4th= x+6

2(x + (x+4)) = 3(x+6)-20

4x+8 = 3x+18–20

4x-3x=18–20–8

x=-10

So the numbers are -10, -8, -6, -4

first 2nd 3rd 4th

Check:

2( -10-6) = 3(-4) -20

2(-16) = -12-20

-32 = -32