Question

What are the zeros of this function (g)(x)=3x^2-33x-180

Answer 1

3x² - 33x - 180 = 0

3(x² - 11x - 60) = 0

3(x - 15)(x + 4) = 0
(x - 15)(x + 4) = 0

x - 15 = 0 or x + 4 = 0

x = 15 or x = -4

Answer 2

3x²-33x-180=3(x²-11x-60)=3(x-15)(x+4)

The roots are x-15=0, x=15 and x+4=0, x=-4