Answer:
The volume of the sphere is increasing at a rate of 56,549 cubic millimeters per second.
Explanation:
Volume of a sphere:
The volume of a sphere is given by:
![V = (4\pi r^3)/(3)](https://img.qammunity.org/2022/formulas/mathematics/college/fapont2kxv1uk7tvfcy81ld7ax7asf1n43.png)
In which r is the radius.
Solving this question:
The first step do solve this question is derivating V implictly in function of t. So
![(dV)/(dt) = 4\pi r^2 (dr)/(dt)](https://img.qammunity.org/2022/formulas/mathematics/college/yk5t39tu3asycq5s7upjuhkyldyi2zei2q.png)
The radius of a sphere is increasing at a rate of 5 mm/s.
This means that
![(dr)/(dt) = 5](https://img.qammunity.org/2022/formulas/mathematics/college/ouh6pr3x6zg60y6yrqh9jkkrtm89t4bcsf.png)
Diameter is 60 mm
This means that
![r = (60)/(2) = 30](https://img.qammunity.org/2022/formulas/mathematics/college/yyq5ckqafum2222e4c78ark9okcqi4ui4w.png)
How fast is the volume increasing (in mm3/s) when the diameter is 60 mm?
This is
. So
![(dV)/(dt) = 4\pi r^2 (dr)/(dt)](https://img.qammunity.org/2022/formulas/mathematics/college/yk5t39tu3asycq5s7upjuhkyldyi2zei2q.png)
![(dV)/(dt) = 4\pi*30^2*5 = 900*20\pi = 56549](https://img.qammunity.org/2022/formulas/mathematics/college/wleg596jk631a6tzaeqmbvj65wy4d5pp2e.png)
The volume of the sphere is increasing at a rate of 56,549 cubic millimeters per second.