95.6k views
0 votes
Complete the square for the following quadratic equation to determine its solutions and the location of its extreme value.

y=-x^2+4x+12

1 Answer

2 votes

Answer:

x^2+4x+12=(x+3)^2+3

Explanation:

x^2+4x+12

(1/2×6)^2=(3)^2=9

x^2+4x+(3)^2-(3)^2+12

x^2+4x+9-9+12

(x+3)^2-9+12

(x+3)^2+3

hope I helped.

User Kyle Sponable
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories