Answer:
P = 48 in²
Explanation:
Given: A rectangle; Width = 9 inches, length = 15 inches, enlarged by a scale factor of
![(3)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/mnscco4nc1evl769d3cq30sp05j8za9ox9.png)
To find: Perimeter of the dilated rectangle
Formula:
![P=2(l+w)](https://img.qammunity.org/2022/formulas/mathematics/high-school/3wlayixf1k4scpsk8uxsxvkvksjzlojwrn.png)
Solution: After a dilation with a scale factor of one-half, then the lengths on the image would be one-half , one-half , and one-half . To find the perimeter of an enlarged figure, you can multiply the original figure's perimeter by the scale factor.
×
![(15+9)=48in](https://img.qammunity.org/2022/formulas/mathematics/college/v0jlt521gy7mas4rwt4c95j4i1euphdfgp.png)
Therefore, the perimeter of the detailed rectangle that was enlarged is 48 in²