Answer:
The particle moves to the right when 0 ≤ t < a
Step-by-step explanation:
Since at any time t≥0 its position is given by x(t) = 12(a−t)², the particle moves to the right if x(t) > 0
So, x(t) > 0 ⇒ 12(a−t)² > 0 ⇒ (a−t)² > 0
So, (a−t)² > 0
taking square-root of both sides, we have
√(a−t)² > √0
⇒ (a−t) > 0
⇒ a > t
Since t ≥ 0 ⇒ a > t ≥ 0 ⇒ 0 ≤ t < a
So, the particle moves to the right when 0 ≤ t < a