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A block attached to an ideal spring oscillates horizontally with a frequency of 4.0 Hz and amplitude of

0.55 m. The spring constant is 75N/M
What is the mass of the block?

2 Answers

3 votes

Final answer:

The mass of the block attached to the spring is found to be approximately 0.149 kg or 149 grams, calculated using the formula relating frequency, mass, and spring constant.

Step-by-step explanation:

The student has asked to find the mass of a block oscillating on a spring with a frequency of 4.0 Hz and a known spring constant of 75 N/m. The relationship between the mass (m), spring constant (k), and frequency (f) of a simple harmonic oscillator is given by the formula f = 1/(2π)∙√k/m. Solving for the mass yields m = k/(4π²f²).

In this case, the frequency (f) is 4.0 Hz and the spring constant (k) is 75 N/m:

m = 75 N/m / (4π² × (4.0 Hz)²) = 75 / (16π²) = 0.149 kg

Therefore, the mass of the block is approximately 0.149 kg or 149 grams.

User Gugge
by
4.8k points
2 votes

Answer:

.12kg

Step-by-step explanation:

khan academy

User Clive Van Hilten
by
4.0k points