Twice the square of an integer added to 6 is 12 times larger than the integer, form qn equation

asked Apr 18, 2023 31.0k views

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14 votes

Integer be x

$\\ \rm\rightarrowtail 2x^2+6=12x$

$\\ \rm\rightarrowtail 2x^2-12x+6=0$

Equation is

$\\ \rm\rightarrowtail x^2-6x+3=0$

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