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Twice the square of an integer added to 6 is 12 times larger than the integer, form qn equation​

User Kaarto
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1 Answer

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Integer be x


\\ \rm\rightarrowtail 2x^2+6=12x


\\ \rm\rightarrowtail 2x^2-12x+6=0

Equation is


\\ \rm\rightarrowtail x^2-6x+3=0

User Highlycaffeinated
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