Question

A A Straight line passes through A(-2,1) and B(2,-k). The

line is perpendicular to a line 3y+2x=5 . determine k
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Answer 1

Given :

A Straight line passes through A(-2,1) and B(2,-k).

The line is perpendicular to a line 3y+2x=5 .

To Find :

The value of k.

Solution :

Let, slope of line is m.

We know, product of slope of in straight line is -1.

`m * (-2)/(3) = -1\\\\m = (3)/(2)`

We know, slope is given by :

`(y_2-y_1)/(x_2-x_1) = (3)/(2)\\\\(1-(-k))/(-2 - 2) = (3)/(2)\\\\(1+k)/(-4) = (3)/(2)\\\\k = -7`

Therefore, the value of k is -7.