Answer:
b; 1 real root and 2 imaginary roots
Explanation:
From here, we have
x(x^2 + 121) = 0
x = 0 (1 real root)
or
x^2 + 121 = 0
x^2 = -121
x = √(-121) (2 imaginary roots)
so is would be two complex numbers from above
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