Question

Find the number of grams of calcium chloride needed to prepare 500.0ml of a 4.0m solution

Answer 1

222 g

Step-by-step explanation:

First we convert 500.0 mL to L:

• 500.0 mL / 1000 = 0.500 L

Then we use the definition of molarity to calculate how many calcium chloride moles are required:

• Molarity = moles / liters

• Molarity * liters = moles

• 4.0 M * 0.500 L = 2.00 mol

Now we convert 2.00 moles of calcium chloride into grams, using its molar mass:

• 2.00 mol * 111 g/mol = 222 g