Question

`x {}^(2) / a + y {}^(2) / b = 1`
find x​

Answer 1

`x=\sqrt{(a(b-y^2))/(b)}`

Explanation:

The given equation is :

`x^2/ a+y^2/ b=1`

We need to find the value of x.

It can also written as :

`(x^2)/(a)+(y^2)/(b)=1`

Subtract
`(y^2)/(b)` from both sides,

`(x^2)/(a)+(y^2)/(b)-(y^2)/(b)=1-(y^2)/(b)\\\\(x^2)/(a)=(b-y^2)/(b)\\\\\text{Cross multiplying both sides}\\\\x^2=(a(b-y^2))/(b)\\\\x=\sqrt{(a(b-y^2))/(b)}`

Hence, the value of x is equal to
`\sqrt{(a(b-y^2))/(b)}`.