Final answer:
The velocity of a 10.0 kg ball as it strikes the ground after falling from a 7.00 m height is approximately 11.72 m/s towards the ground, calculated using the free fall motion equation.
Step-by-step explanation:
The question asks for the velocity of a 10.0 kg ball as it strikes the ground after falling from a 7.00 m height. To find this, one can use the equation of motion under the influence of gravity, which is free fall. The equation v^2 = u^2 + 2gh can be used where v is the final velocity, u is the initial velocity (which is 0 for a free fall), g is the acceleration due to gravity (9.8 m/s^2), and h is the height (7.00 m).
Plugging in the values: v^2 = 0 + 2 * 9.8 m/s^2 * 7.00 m gives us v^2 = 137.2 m^2/s^2. Therefore, v = √137.2 m^2/s^2, which is approximately 11.72 m/s towards the ground. This is the velocity of the ball when it strikes the ground.