Question

If ST=5x+1 and TQ =2(x+5) calculate SQ. PLEASE HELP REALLY HARD

Answer 1

We know

• Diagonals of a parallelogram bisect each other
• ST=TQ

Equate

• 5x+1=2(x+5)
• 5x+1=2x+10
• 3x=9
• x=3

TQ=2(3+5)=16

• SQ=2(16)=32

Answer 2

• B. 32

Explanation:

Diagonals of a parallelogram bisect each other.

T is the midpoint of SQ, so:

• ST = TQ
• 5x + 1 = 2(x + 5)
• 5x + 1 = 2x + 10
• 5x - 2x = 10 - 1
• 3x = 9
• x = 3

Find SQ

• SQ = 2(ST) = 2(5*3 + 1) = 2(16) = 32

Correct choice is B