Question

Triangle IJK, with vertices I(-9,-8), J(-5,-6), and K(-7,-3), is drawn on the coordinate grid below.

Answer 1

`Area= 8`

Explanation:

Given

`I = (-9,-8)`

`J = (-5,-6)`

`K = (-7,-3)`

The complete part of the question is to calculate the area of IJK

The area is calculated using:

`Area = (1)/(2)|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3 |`

Where:

`I = (-9,-8)` ---
`(x_1,y_1)`

`J = (-5,-6)` ---
`(x_2,y_2)`

`K = (-7,-3)` ---
`(x_3,y_3)`

So, we have:

`Area = (1)/(2)|(-9*-6) - (-5*-8) + (-5*-3) - (-7*-6) + (-7*-8) - (-9*-3) |`

Solve the brackets

`Area = (1)/(2)|54 - 40 + 15- 42 + 56 - 27 |`

`Area = (1)/(2)|16|`

The absolute value of 16 is 16

So:

`Area = (1)/(2) * 16`

`Area= 8`