228k views
5 votes
The tip of a windshield wiper travels a distance of 31 inches in one 90 revolution. What is the

length of the windshield wiper to the nearest inch?
F 10 in.
G 15 in.
H 20 in.
J 39 in.
PLEASE HELP!!1

User HAcKnRoCk
by
7.4k points

1 Answer

4 votes

Answer:

Option F, 10 inches.

Explanation:

For a circle of radius R, the perimeter is:

P = 2*pi*R

such that pi = 3.14

If we have a section of that circle defined by an angle θ, the length of the arc is:

A = (θ/360°)*P = (θ/360°)* 2*pi*R

In this case, we have a circle whose radius is defined by the length of the windshield wiper.

We also know that in one 90° revolution (so it travels the length of the arc of 90° two times) the tip travels a distance of 31 in.

Then:

A = 2*[(90°/360°)*2*3.14*R] = 31in

We need to solve this for R.

R = 31in/( 2*(90°/360°)*2*3.14) = 9.8in

We can round this to the next whole number:

R = 10in

The correct option is F.

User Rui Vieira
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories