Answer:
The system of inequalities is:

The graphs are provided below as well. The portion where the shaded region intersect are all the possible points.
Explanation:
Let x represent the amount of stationery sets sold, and let y represent the amount of greeting sets sold.
The goal is to sell at least 100 items. So, the sum of x and y should be at least 100. In other words:

Another goal is to raise at least $300. Since each stationery set sells for $2.50 and each greeting set sells for $3.00, we can write:

So, our system of inequalities is:

To graph, we can first graph them as lines. Rewrite the equations:

And:

Ignore the inequalities and graph the lines. This is shown in the first graph below.
Both inequalities have "or equal to," so we have solid lines.
Finally, since both inequalities have y as "greater than" the equation, our shaded portion will be above the lines. This is shown in the second graph. The portion where both shaded regions covers are all the feasible points.