Answer:
20654 N
Step-by-step explanation:
Applying
F = kqq'/r²........... equation 1
Where F = Force between the charge, q = First charge, q' = second charge, r = distance betweeen the charge, k = coulomb's constant.
From the question,
Given: q = -0.0004 C, q' = 0.00092 C, r = 0.4 m
Constanr: k = 8.98×10⁹ Nm²/C²
Substitute these values into equation 1
F = ( -0.0004×0.00092×8.98×10⁹)/(0.4²)
F = (3.30464×10³)/0.16
F = (3304.64)/0.16
F = 20654 N
Hence the force between the charges is 20654 N