Answer:
F' = 9 F
Step-by-step explanation:
The question says that, "If the linear speed of a mobile moving with MCU is tripled and the radius remains constant, then the centripetal force:"
The formula for the centripetal force is given by :
![F=\frac{mv^2}r{}](https://img.qammunity.org/2022/formulas/physics/high-school/vsclm9t8ngxfhlu81b5xv63pt1jgqlqliy.png)
Where
m is the mass of the object
v is the velocity
r is the radius of path
If the linear speed us tripled, v' = 2v, r = constant, then the new centripetal force is given by :
![F'=\frac{mv'^2}r{}\\\\F'=(m(3v)^2)/(r)\\\\=(mv^2)/(r)* 9\\\\F'=9F](https://img.qammunity.org/2022/formulas/physics/high-school/c5kvbuyusmlc0fjws1ntxr55m6iagee2l5.png)
So, the new force becomes 9 times of the initial force.