Question

What is the equation of a line that passes through the points (0, 5) and (4, 8)? Write your answer in slope-intercept form (y = mx + b). ( help pleaseee )

Answer 1

This will need become a point slope form.

First we need to find slope

(Y2-Y1/X2-X1)

(8-5/4-0) = (3/4)

Slope = (3/4)

Now for the point slope equation

y - y1 = m(x-x1)

Plug in one of the points and the slope

y - (5) = 3/4(x - (0))

Let’s convert to y = mx + b formatting

y - (5) = 3/4(x - (0))

y - 5 = 3/4x - (3/4)(0)

y - 5 = 3/4x

y = 3/4x + 5

This will be your equation.