Question

What is the 12th term of the geometric sequence where *

A7 = 7 and 10 = -56
O-448
0-224
O -112
0 -96

Answer 1

Explanation:

A7 = 7

A10 = -56

7xRxRxR = -56

R = -2

A12 = A10xRxR

= -56 x -2 x -2

= 224

Answer 2

-224

Explanation:

Geometric sequence is given by An = A*R^(n-1)

Given A7 = 7 and A10 = -56

A10/A7 = -8 = R^(10-7)

R^3 = -8

R = -2

A12 = A10*R^2

= -56*-2^2

= -224