Answer:
110.92 g
Step-by-step explanation:
Amount of Ni2O3 consumed= 55.3/59 =0.94 moles
From the reaction equation;
2 moles of Ni2O3 yields 4 moles of Ni
0.94 moles yields 0.94 moles * 4/2
= 1.88 moles of Ni2O3
Mass of 1.88 moles of Ni2O3 = 1.88 moles of Ni2O3 * 59 gmol-1 = 110.92 g