131k views
5 votes
Triangle ABC has vertices located at A(1, -4), B(4, -6) and C(2, -1) on a coordinate grid. After it is reflected across the y-axis and a dilation of ½ is applied, what is the new coordinate of B? A. (4,6) B. (8,12) C. (2,3) D (-2, -3)

User Sungjun
by
4.0k points

1 Answer

3 votes

Answer:


B' = (-2,-3)

Explanation:

Given


A = (1,-4)


B = (4,-6)


C = (2,-1)

reflection across y


d = (1)/(2)

Required

New coordinate of B

When reflected across the y-axis.

The rule is:


(x,y) \to (-x,y)

So:


(4,-6) \to (-4,-6)

Next is a dilation by 1/2

To do this, we multiply the new point by 1/2

So:


B' = (-4,-6) * (1)/(2)


B' = (-4* (1)/(2),-6* (1)/(2))


B' = (-2,-3)

User DV Singh
by
3.8k points