59,368 views
6 votes
6 votes
8. Write the equation of the line that is parallel to the line 2x + 5y = 15 and passes through the

point (-10, 1).

User Caleb Syring
by
2.9k points

2 Answers

20 votes
20 votes

Solution:

Step-1: Convert the line into slope intercept form.

  • 2x + 5y = 15
  • => 5y = -2x + 15
  • => y = -0.4x + 3

Step-2: Use the point slope form formula.

  • y - y₁ = m(x - x₁)
  • => y - 1 = -0.4{x - (-10)}
  • => y - 1 = -0.4{x + 10}
  • => y - 1 = -0.4x - 4
  • => y = -0.4x - 3
User Ozarov
by
3.1k points
24 votes
24 votes

Answer:


\sf y = \bold -(2)/(5) x -3

Step-by-step explanation:

part A identification for slope:


\sf 2x + 5y = 15


\sf 5y = -2x + 15


\sf y = (-2x + 15)/(5)


\sf y = -(2 )/(5) x+3

comparing with slope intercept form: y = mx + b

we can find that here the slope is
\bold -(2)/(5)

part B, solving the equation:

if the line is parallel, then the slope will be same.

given coordinates: ( - 10, 1 )

using the equation:

y - y₁ = m( x - x₁ )


\sf y - 1 = \bold -(2)/(5) (x --10)


\sf y = \bold -(2)/(5) x -4 + 1


\sf y = \bold -(2)/(5) x -3

Extra information:

check the image below. this proves that the line is parallel and passes through point (-10, 1). the blue line is question line and red the answer line.

8. Write the equation of the line that is parallel to the line 2x + 5y = 15 and passes-example-1
User Tavakoli
by
3.1k points
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