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❤️ i need this last question

❤️ i need this last question-example-1
User Praveenpds
by
7.9k points

1 Answer

1 vote

Answer:
10\left(\cos90^(\circ)+i\sin90^(\circ)\right)

Explanation:

Given

The complex number is
z_1=0+10i

Complex number in polar form is given by


z=r\left(\cos \theta +i\sin \theta\right)

Compare it with the given complex number


r=10 and
\sin \theta=1 which implies
\theta must be
90^(\circ)

So, in the polar form, it is


z_1=10\left(\cos90^(\circ)+i\sin90^(\circ)\right)\\z_1=10e^{i(\pi)/(2)}

User Tek Yin
by
7.9k points

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