Answer:
2.44 L
Step-by-step explanation:
Step 1: Write the balanced equation
2 Ca + O₂ ⇒ 2 CaO
Step 2: Calculate the mass of O₂ required to form 11.2 g of CaO
The molar mass of O₂ is 32 g/mol and in the balanced reaction, there is 1 mole of O₂, that is, 1 mol × 32 g/mol = 32 g.
The molar mass of CaO is 56 g/mol and in the balanced reaction, there are 2 moles of CaO, that is, 2 mol × 56 g/mol = 112 g.
11.2 g CaO × 32 g O₂/112 g CaO = 3.2 g O₂
Step 3: Calculate the volume occupied by 3.2 g of O₂
Under the conditions of the task, 32 g of O₂ occupy 24.4 L.
3.2 g × 24.4 L/32 g = 2.44 L