Question

Find a vector length of 5m in the xy plane that is perpendicular to A=3i+6j+2k hint use dot product​

Answer 1

Step-by-step explanation:

vector A =(3i^+4J^-2k^),

let the required vector is B = x i^ + y j^

sqrt (x2 + y2) = 5,

x2 + y2 = 25 ..............(1)

Since vector A and B are perpendicular to each other then,

A.B = 0

3x + 4 y = 0

y = -3x/4 ..............(2)

Solving these two equations we get x = 4 and y = -3;

hence vector B = 4 i^ -3 j^