Question

Q.4) Two table tennis balls hang with their centers 10.0 cm apart. The charge on ball

A is +12x10°C, and the charge on Ball B is -15x10°C. What is the force of
attraction between the balls?

Answer 1

F = 1.62 x 10¹⁴ N

Step-by-step explanation:

The electrostatic force of attraction between the balls can be given by the following formula:

`F = (kq_1q_2)/(r^2)`

where,

F = attractive force = ?

k = Colomb's Constant = 9 x 10⁹ N.m²/C²

q₁ = Charge on ball A = 12 C

q₂ = Charge on ball B = 15 C

r = distanc between the balls = 10 cm = 0.1 m

Therefore,

`F = ((9\ x\ 10^9\ Nm^2/C^2)(12\ C)(15\ C))/((0.1\ m)^2)`

F = 1.62 x 10¹⁴ N