Given:
Let us consider the given sides are:
![BD=21m](https://img.qammunity.org/2022/formulas/mathematics/high-school/2pahz1gcix6eqvm9pwtd3fkcaq1o4ru157.png)
![BC=25m](https://img.qammunity.org/2022/formulas/mathematics/high-school/728eycn1fjnue8evqombfpxtrajhgb1cvv.png)
![DE=40m](https://img.qammunity.org/2022/formulas/mathematics/high-school/kdpj7z8kp473jikkvyrnyk3bkezbe5ixp6.png)
![AB=xm](https://img.qammunity.org/2022/formulas/mathematics/high-school/rgv8vor7p3fe6da6hzgpj2pesblazfhmcq.png)
To find:
The length of side AB.
Solution:
Suppose the measure of AB be x.
From the given figure it is clear that,
(Right angles)
(Corresponding angles)
In triangles ABC and ADE, two corresponding angles are congruent. So, by AA property of similarity,
![\Delta ABC\sim \Delta ADE](https://img.qammunity.org/2022/formulas/mathematics/high-school/oi6ierwk9jy6pt607x0rh6ikofsrwzumon.png)
We know that, corresponding sides of similar triangle are proportional.
![(AB)/(BC)=(AD)/(DE)](https://img.qammunity.org/2022/formulas/mathematics/high-school/j74abmop8ues9fc23t0et6m61ozgoubo65.png)
![(x)/(25)=((x+21))/(40)](https://img.qammunity.org/2022/formulas/mathematics/high-school/dc87o2de5qqfiumzwak8mj25m7kdczyoyv.png)
![40x=25(x+21)](https://img.qammunity.org/2022/formulas/mathematics/high-school/27l8jqdqy793ho6x7hlbcu35lsg5nq6nvs.png)
![40x=25x+525](https://img.qammunity.org/2022/formulas/mathematics/high-school/ag2st07drm1qdbn3otkjtqpe4vmpsf1gtq.png)
Isolating the x terms, we get
![40x-25x=525](https://img.qammunity.org/2022/formulas/mathematics/high-school/dk58kg0i7mgdcag2lwauu0k12hbrdwol0z.png)
![15x=525](https://img.qammunity.org/2022/formulas/mathematics/high-school/3tcmnxo8vw5qpnho4mw01jois7a4kan4jp.png)
![x=(525)/(15)](https://img.qammunity.org/2022/formulas/mathematics/high-school/lvq6yxok00oxjmvpr1bl2qs1hamnnvgzez.png)
![x=35](https://img.qammunity.org/2022/formulas/mathematics/high-school/e6bb0im43f7lt7q8hkksss0cjxj56myhdm.png)
Hence, the measure of AB is 35 m.