Question

Aluminum has an alpha value of 25 x 10^-6 1/degrees C. What is the change in

length of a 4850 cm wire at 2 degrees C when the temp increase to 55 degrees
C?

Answer 1

0.25705 cm or 2.5705×10⁻³ m

Step-by-step explanation:

Applying,

α = ΔL/(LΔT)................. Equation 1

Where α = coefficient of linear expansivity, ΔL = Increase in length, L = Original length, ΔT = Increase in temperature

make ΔL the subject of the equation

ΔL = α(LΔT)............... Equation 2

From the question,

Given: α = 10⁻⁶ C⁻¹, L = 4850 cm, ΔT = T₂-T₁ = (55-2) = 53 °C

Substitute these values into equation 2

ΔL = (10⁻⁶)(4850)(53)

ΔL = 0.25705 cm or 2.5705×10⁻³ m