Question

A hydraulic system is lifting a 11760 N car using a cylinder with an area of 0.25 m

squared. What force is applied to the small cylinder if it has an area of 0.0125 m
squared?

Answer 1

F₂ = 588 N

Step-by-step explanation:

Given that,

Force, F₁ = 11760 N

Area of the cylinder, A₁ = 0.25 m²

Force on small cylinder, F₂ = ?

The area of the small cylinder, A₂ = 0.0125 m²

We know that, according to Pascal's law,

`P_1=P_2\\\\(F_1)/(A_1)=(F_2)/(A_2)\\\\F_2=(F_1A_2)/(A_1)\\\\F_2=(11760 *0.0125 )/(0.25 )\\\\F_2=588\ N`

So, the force on the small cylinder is equal to 588 N.